Question

This post is too short to fit the entire question
(Please see next post)

Answer 1

3Cu(s) + 2MnO4- (aq) + 8H+(aq) ---> 3 Cu2+(aq) + 2 MnO2(s) + 4H2O(l)
I was trying to write a cell diagram for this, but then I realized that there is also a (l) form, and stoichiometric coefficients are involved, so I got quite confused.

My Try:
Cu(s) | Cu2+(aq) || MnO42-(aq) , 8H+(aq) | MnO2(s) | H2O(l)

The equation for the MnO42- reduction is:
MnO4-(aq) + 4H+(aq) + 3e- --> MnO2(s) + 2H2O(l)
(I had to balance the e- for the equation of the question so that is why I ended up with 8H+ and not 4H+).

In short, my questions are:
a) is my try correct?
b) do we ever include stoichiometric coefficients in cell diagrams?

Answer 2

The oxidation equation, by the way, is:
Cu(s) ---> Cu2+(aq) + 2e-