the height of a ball thrown straight up with a velocity of 96 ft/s is given by the quadratic function h(t)= -16t^2 +96t. what is the maximum height the ball reaches?

Question

anonymous · Answer

to find this take the derivative and set it equal to 0. -32t+96=0
solve t=3 plug back in to the original. = 144

campbell_st · Answer

a simple way is to find the line of symmetry and sub it into the original equation 

t = -96/-32 t =3

max height is when t = 3 sub into the original equation

campbell_st · Answer

the line of symmetry comes from the general quadratic formula 

its just x = -b/2a   in this question b = 96 and a = -16  so its -96/(2x-16)

anonymous · Answer

thanks