A volume of 18.0L contains a mixture of 0.250mole N2, 0.250mole O2, and an unknown quantity of He. The temperature of the mixture is 0 degree C, and the total pressure is 1.00atm. How many grams of helium are present in the gas mixture?

Question

anonymous · Answer

First find the total moles of the substance with our handy dandy pivnert equation.$$PV=nRT$$$$n={(1.00atm)(18.0L)(mol)(K)\over(273.15K)(.08206L)(atm)}$$ Then we find subtract the moles of N2 and O2 from the moles we found and convert to grams with molar mass.