Question

How do I solve this equation? 25(x+2)^2-2=0

Answer 1

get the (x+2)^2 by itself first! :)

Answer 2

1)Add 2 on both sides
2)Divide by 25 on both sides

Answer 3

Doing it right now

Answer 4

(x+2)^2=2/25?

Answer 5

Take a square root on both sides,

\[(x+2) = \sqrt{ \frac{2}{25}}\]

Answer 6

\[x+2 = \frac{\sqrt2}{\sqrt{25}}\]

Answer 7

\[x+2 = \pm \frac{\sqrt2}{5}\]

Answer 8

\[x+2=\sqrt{2}/5\]

Answer 9

dont forget the positive and negative sign.

Answer 10

oh ya, now how do I get x by itself?

Answer 11

use a calc,
\(x = \frac{\sqrt2}{5} - 2\) and \(x = -\frac{\sqrt2}{5} - 2\)

Answer 12

Thanks

Answer 13

Welcome.

Answer 14

would \[-2+-\sqrt{2}/5 \] be the same?

Answer 15

Nope, we will get 2 different answers.

Answer 16

would \[2+-\sqrt{2}/5\]be?

Answer 17

\[-2+(-\frac{\sqrt2}{5}) = 1.7\]

Answer 18

And \[+2+\frac{\sqrt2}{5} = 2.28\]

Answer 19

\[2 \pm \frac{\sqrt{2}}{5} ?\]

Answer 20

that form?

Answer 21

yes:)

Answer 22

by the way that is -2 not positive 2

Answer 23

\[-2 \pm \frac{\sqrt{2}}{5}\]

Answer 24

\[x+2 = \pm \frac{\sqrt{2}}{5}\]
Subtract 2 on both sides
\[x=-2 \pm \frac{\sqrt{2}}{5}\]

Answer 25

25[x2+4x+4]-2=0
25x2+100x+100-2=0
25x2+100x+98=0
using formula,solve for quadratic equation
though Saifoo's method is better...