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Chemistry 7 Online
OpenStudy (anonymous):

cation, anion, and compound for 1s22s22p63s1 and 1s22s22p4

OpenStudy (prakharluv):

the element with e.c. 1s2,2s22p6,3s1is SODIUM (Na). Na lose it single outermost valance electron to form Na+and become stable... the element with e.c.1s2,2s22p4 is OXYGEN (O). O gain two electron to form O2- and become stable..... Sodium reacts with oxygen to form sodium peroxide. 2Na + O2 \[\rightarrow\] Na2O2.

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