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OpenStudy (anonymous):
cation, anion, and compound for 1s22s22p63s1 and 1s22s22p4
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OpenStudy (prakharluv):
the element with e.c. 1s2,2s22p6,3s1is SODIUM (Na). Na lose it single outermost valance electron to form Na+and become stable... the element with e.c.1s2,2s22p4 is OXYGEN (O). O gain two electron to form O2- and become stable..... Sodium reacts with oxygen to form sodium peroxide. 2Na + O2 \[\rightarrow\] Na2O2.
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