Question

PLEASE HELP ME!!! I DONT GET IT PLEASE >_<
how many times does the graph of y=3x^2+4x-1 intersect the x-axis

Answer 1

find the x intercepts

Answer 2

make y=0

Answer 3

O yea and also these are the
A)three
B)two
C)one
D)none

Answer 4

how can I make them y=0

Answer 5

well
proabola usually has 2

Answer 6

parabola*

Answer 7

use the discriminant which is

\[b^2 - 4ac\]

when the general form of the quadratic is ax^2 + bx + c

in your question a = 3, b = 4 and c = -1

then 4^2 - 4 x 3 x (-1) = 28

since discriminant is > 0 then it cuts the x axis twice

Answer 8

u can also try factoring

Answer 9

Solve this.
\[
y=3x^2+4x-1\;\text{when}\;y=0
\]

Answer 10

wut cambell said would be correct use the discriminant of the quadratic formula b^2-4ac

Answer 11

ok I havent learned discriminant of the quadratic formula

Answer 12

the conditions of the deiscriminant are

\[b^2 - 4ac > 0\] there are 2 unequal roots. If the discriminant is a square number the roots are unequal and rational
\[b^2 - 4ac = 0\] one repeated root
\[b^2 - 4ac < 0\] no real roots

Answer 13

u should've learned how to factor atleast therefore when finding the x coordinates it means that that point is on the x axis which means that the f(x) passes through the x axis

Answer 14

if you haven't learnt the discriminant then use the general quadratic formula to find the roots

\[x = (-4\pm \sqrt{4^2 - 4 \times3\times-1})/(2\times6)\]

Answer 15

ok that works i know that one general quadratic formula to find the roots ill do that

Answer 16

I will also try and factor

Answer 17

factoring won't work