Question

what is the derivative of x(2x-3)^1/2?

Answer 1

(2x-3)^(1/2) + x(2x-3)^(-1/2)

Answer 2

what about the 2 that is taken from the inside of the function? and thats what i have already but i dont know how to simplify it further

Answer 3

That 2 has been cancelled by 1/2 from the exponent. Do you have some answer you have to simplify for?

Answer 4

oh thanks butthis isnt an integration problem

Answer 5

the other options are
a) 3x-3/ sqrt2x-3
b.) x/sqrt 2x-3
c.) 1/sqrt 2x-3
d.)-x+3/ sqrt 2x-3
e.)5x-6/2 sqrt 2x-3

Answer 6

Simply add the terms, you will get 3x-3/(2x-3)^(1/2)...Know how?

Answer 7

no the final step im on is (2x-3)^1/2 +(2x)(1/2)(2x-3)^-1/2

Answer 8

Ok, look, we have,
(2x-3)^(1/2) +x(2x-3)^(-1/2)
=> [(2x-3)^(1/2) * (2x-3)^(1/2) + x ]/(2x-3)^(-1/2)
=>(2x-3+x)/(2x-3)^(-1/2)
=>3x-3/(2x-3)^(1/2)

Answer 9

ah i feel th feel like i have made this problem harder than it neeeds to be but, why did you multiply (2x-3)^(1/2) by (2x-3)^(1/2) in the second step?

Answer 10

Its the way you add surds, multiply the denominator and join them.

Answer 11

ok thanks! I really appreciate you're patience

Answer 12

I wish i could have done that in proper latex so it'd have been clear before.

Answer 13

where are you from? what country?