find the slope of the curve y = x^2 (x+2)^2 at point (1,2) a. 81 b. 48 c. 64 d. 54
take the derivative, replace x by 1
my answer is 64 i got wrong... i just wanted to know the answer...
\[x^2(x+2)^2=x^2(x^2+4x+4)=x^4+4x^3+4x\] \[y'=4x^3+12x^2+4\] i get 20
the answer is in the letter i just forgot..and i need it
oh i made a mistak
\[x^2(x+2)^2=x^2(x^2+4x+4)=x^4+4x^3+4x^2\] \[y'=4x^3+12x+8\] now i get 24
i get 24 omg
wth
there is no point 1,2 on this curve
OMG MY CLASSMATE KING
KINGkos is review his quiz and exam too hahahahha
so the truth is revealed haha
on tuesday is final exam thats y i memorized all the answer in quiz and homework.this question is my X in the quiz
your question makes no sense ... chk it for typos
http://openstudy.com/study#/updates/4f8a50eae4b09e61bffc0287 correct question
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