For y = x2 + 6x - 16,

Determine if the parabola opens up or down.
State if the vertex will be a maximum or minimum.
Find the vertex.
Find the x-intercepts.
Describe the graph of the equation.

Question

For y = x2 + 6x - 16,

    Determine if the parabola opens up or down.
    State if the vertex will be a maximum or minimum.
    Find the vertex.
    Find the x-intercepts.
    Describe the graph of the equation.

anonymous · Answer

$$y=x^2+6x-16$$ like 
$$y=ax^2+bx+c$$ open up because $a>0$

anonymous · Answer

I only need to
Find the x-intercepts.
AND
 Describe the graph of the equation.

anonymous · Answer

since it opens up vertex is a min

anonymous · Answer

vertex is $-\frac{b}{2a}=-\frac{6}{2}=-3$ for the first coordinate, second one is -25

anonymous · Answer

x intercepts
$$x^2+6x-16=0$$
$$(x+8)(x-2)=0$$
$$x=-8, x = 2$$

anonymous · Answer

to graph, put a parabola that opens up with vertex (-3,-25) and crosses x axis at (-8,0) and (2,0)