Find the anti derivative of

(x-5)^(2)(x+1)/(x-1)

so I did a double substitution
set
u = (x - 5)
du = dx
then
s = (u-4)
s + 4 = u
ds = du

which got me here as I just kept breaking up the integral.

(x-9)^(3)/3 + 8(x-9)^(2)/2 + 20(x-9) + 16ln|x-9| + 24ln|x-9| + 6|x-9| + c

Question

Find the anti derivative of

(x-5)^(2)(x+1)/(x-1)

so I did a double substitution
set 
u = (x - 5)
du = dx
then
s = (u-4)
s + 4 = u
ds = du

which got me here as I just kept breaking up the integral.

(x-9)^(3)/3 + 8(x-9)^(2)/2 + 20(x-9) + 16ln|x-9| + 24ln|x-9| + 6|x-9| + c

anonymous · Answer

((x-9)^(3)/3) + (8(x-9)^(2)/2) + (20(x-9)) + (16ln|x-9|) + (24ln|x-9|) + (6|x-9|) + c

ugh I mean this

anonymous · Answer

is this correct?

experimentx · Answer

simplify and make partial fractions ... that shouldn't be difficult.

anonymous · Answer

yeah it isn't thanks