Question

A certain strain of virus grows in numbers at the rate of 50% per hour. If its present population is
88,000 what will be its population count in 6 hours?

Answer 1

N = A(r)^(t/d)
N = 88000(1.5)^(6/2)

Answer 2

I think, I might be wrong.

Answer 3

Follow along and try to notice the pattern
The amount after 1 hour,
A1 = 88000 + 88000*.5 = 88000(1+.5)
The amount after 2 hours,
A2 = A1 + A1*.5 = A1(1+.5) = 88000(1+.5)(1+.5)
3 hours,
A3 = A2 + A2*.5 = A2(1+.5) = 88000(1+.5)(1+.5)(1+.5)
4 hours,
A4 = A3 +A3*.5 = A3(1+.5) = 88000(1+.5)(1+.5)(1+.5)(1+.5)

So to get An, I just start with 88000 and multiply by (1.5) n times, this is the same as multiplying by (1.5)^n

Answer 4

Petewe, you are almost right. It's just that the power is 6, not 6/2.

Answer 5

So what is the count?

Answer 6

=(

Answer 7

Hours | Population |Can also be written as
0 88000 88000
1 88000*(1.5) 88000*(1.5)^1
2 88000*(1.5)(1.5) 88000*(1.5)^2
3 88000*(1.5)(1.5)(1.5) 88000*(1.5)^3
4 88000*(1.5)(1.5)(1.5)(1.5) 88000*(1.5)^4
...
please notice the pattern and figure out how to find the population after 6 hours on your own