Question

x/2 + y/8 = 4
x/3+y/2=-2
Elimination , please help! :)

Answer 1

maybe clear the fractions first

Answer 2

im not getting the right answer :(

Answer 3

\[\frac{x}{2}+\frac{y}{8}=4\]
\[4x+y=32\] for the first one

Answer 4

\[x/3+y/2=-2\]
\[2x+3y=-12\] for the second one
then work with
\[4x+y=32\]
\[4x+3y=-12\]

Answer 5

\[-4x-y=-32\]
\[4x+3y=-12\]
\[2y=-44\]
\[y=-22\] does that look right ?

Answer 6

When you multiplied the "second" one by two (to get the 4x) why did you not multiply all the terms?

Answer 7

i think i multipied the second one by 6
at least that is what i meant to do

Answer 8

oh i see i messed up didn't i?

Answer 9

Ooh kay

Answer 10

no no i made a mistake

Answer 11

\[4x+y=32\]
\[2x+3y=-12\]should be the system
i messed up

Answer 12

btw did you eliminate x or y?

Answer 13

Which one do you want to eliminate?

Answer 14

y

Answer 15

do i multiply the first one by 1 and the second one by 3?

Answer 16

You need to make the coefficients of y the same.

Answer 17

i tried but it didnt divide evenly

Answer 18

Yes, but no need to multiply the first one by one as it would simply remain the same.

Answer 19

You are on the right track, gotta run.

Answer 20

x-3y=10
12+3=36

13x = 16

Answer 21

it dosent divide evenly

Answer 22

13x=46**

Answer 23

@kellyking, First and foremost you must give up the notion that correct answers are going to be "even"
Sattelite73 showed you how those equations became equal to:
1. 4x + y = 32 and
2. 2x + 3y = -12
You elected to eliminate the y. To do this multiply equation 1 by -3, getting:
1. -12x - 3y =-96 now add equation 2
2. 2x +3y = -12
---------------------
-10x = -108
x= 108/10 = 54/5 Not a pretty answer .....but correct.
Now substitute this value of x (54/5) into equation 2. Getting
2(54/5) + 3y = -12
108/5 + 3y = -12 multiply thru by 5 getting:
108 +15y = -60
15y=-60-108
15y=-168
y=-168/15=-56/5 another odd looking value, but none the less correct solution.
Sorry I had to run last night, but Thurs is my favorite TV night lol.