Trigo problem #2
pi
well first thing you should do is find x = pi/2
to find the height of the triangle, then you need to find the x intercepts to find the length of the base
why is x=pi/2? I found it to be pi/6 and 11pi/6 ...
I meant for the x-ints
then you can just use the standard formula bh/2 to find the area
i found none of these
i found \(A=\frac{1}{2}\)
Well I found pi
oh i mean i did not find these for A and B and C
you would take x = pi/2, because that will give you the height of your triangle because it is at the triangles tip
everybody is getting different answers. lol
So, the answer is C, if it is correct
i did not find the answer yes you need A and B and C i got \(A=\frac{1}{2}\), \(C=3\), \(B=\pi-\frac{1}{2}\)
First you find the height of the triangle to be \(y=1\). Now you need to find the base. Since \[0=1-2\cos(2x)\]At \(x=\pi/6\), we know the base is \(2\cdot (\pi/2 -\pi/6)\) = \(2\pi/3\)
To find the area of the triangle, we multiply by height, which is 1, and divide by 2 to get \(\pi/3\).
i am way way wrong nvm
Oh, I got the answer thanks all :)
what was the answer??
height = 1-2cospi =3 Put y=0 into the equation x=pi/6 or pi = 5pi /6 base = 4pi/6 Area = (4pi/6)(3)(1/2) = pi => that's the answer :)
looks like my little trick worked.
I derped.
@experimentX Would you mind sharing your little trick with us?
\(A=\frac{\pi}{6}, B = 3\) so the rectangle has base \(\frac{\pi}{3}\) and height 3 and area \(\pi\)
1-2cos(2(pi/2)) = 3 0 = 1-2cos(2x) -1/2 = cos(2x) cos(2x) is zero at pi/4 + npi where n is an Integer thus we have roots pi/4 and 5pi/4 so now we just need to subtract them to get the length of the base 5pi/4 - pi/4 = 4pi/4 is the length pi is the length of the base and the height is pi/2 so A = (pi^(2)/2)/2 Area = pi^(2)/4
same as yours, the max height would be 3(max value), that's obvious now get one point on left by equating to zero, since graph is symmetric, (pi/2 - pi/6)*2 must be base
lol made a mistake with final answer Area = 3pi/2
@experimentX Then that's not a trick anymore lol
i will stick with \(\pi\)
thats how ffm works
i must have made a mistake in my calculations oh well :L
could be wrong, but i like \(\pi\)
@satellite73 it's correct :)
Height = 1-2cos(2(pi/2)) = 3 Base = 5pi/4 - pi/4 = pi A = bh/2 A = 3pi/2
I just found out the answer is right in front of me... the pi pic :P
calculated the base of the rectangle via \(\frac{\pi}{2}-\frac{\pi}{6}=\frac{\pi}{3}\) and the height of the rectangle as \(3\) and area as \(3\times \frac{\pi}{3}=\pi\) should have listened to experimentx to begin with
Excuse me.. where is the rectangle?
how can the base be pi/2 - pi/6
the rectangle is the two triangles stuck together
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Oh...I see... Nice trick @satellite73 very cute solution :)
ty
you guys win I'm wrong :)
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