@callisto:)
Graph :S
equate the 2 equations and solve it. That's the idea only :P
Can you try it ?
ok
Ok, so first we rearrange the equation so that the RHS = 0, am i right?
Equate the 2 equations first. Can you show this step first?
Like this? 2 sin(x) - 1 = g(x) - 3 cos(x) + 2
Nope...2 sin(x) - 1 = 3 cos(x) + 2 it's like when you have 2 line and want to find their intersection, you would equate them, got it?
Ohhh okk
Hmm... that's ugly... give me some time first... sorry!!!
Are you supposed to solve it algebraically or graphically?
I think if they wanted it algebraically, they would specify, so I can safely assume its graphically
That would be pretty easier then :)
Can you see the 2 intersection points? that're your answers :)
what? really? but isnt that merely tracing the zeroes?
I dont think its graphically then, LOL
Wait, I've some problems interpreting the question now..
Is there the whole question you have?
Yeah! me too. I was going to ask you if you could rephrase it. Idk why but the author of the book asks questions in a strange manner
Yeah, thats the entire question
Let's fetch helps :)
f = 2sinx - 1 g=3cosx + 2 For f=g, 2sinx - 1 = 3cosx +2 2sinx - 3cosx = 3 It only says equation hehehe there is your equation for the theta or x co-ordinate. (f - 1)/2 = sinx (g-2)/3 = cos x \[\sin^2x +\cos^2 x =1\implies (f-1)^2/4 + (g-2)^2/9 = 1\]
OpenStudy? ARE YOU NOT ENTERTAINED!?!?! :D
What? what do you mean?
http://www.youtube.com/watch?v=FsqJFIJ5lLs I meant are you satisfied with my answer?
Ohh. Its better than anything I would get:) Thank you
hahaha. nice touch with the video:)
lol
wait so which one is the equation? This one? sin2x+cos2x=1⟹(f−1)2/4+(g−2)2/9=1
the later one\[(f-1)^2/4 + (g-2)^2/9 = 1\]
Oh ok. Sorry, I have been awake for 23 hours, Im not thinking straight:) Thank you
wait it's f+1 not f-1 sorry
@Ishaan94 What is the use of the following steps in your solutions? For f=g, 2sinx - 1 = 3cosx +2 2sinx - 3cosx = 3
That's for getting the x co-ordinate or the theta for the curve intersection.
Hmmm... I'm totally lost... sorry!!!!!!
The question asks, "What equation would have the intersection points of the graphs as its solution?" It is (reasonably) clear that the equation they want is when the two curves equal each other. Of course, the proof is in the pudding. If we solve your equation, we see that the solutions are in fact the intersection points shown in the question (112.6º and 180º)
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