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Plane geometry question #2 - centres in a triangle
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I'm useless, sorry
Orthoscenter is and intersection of the three altitudes of a triangle. To find it first find a line equation of each of the sides of the triangle and their respective perpendicular line pasing thru the respective vertice. Then just find their intersection point....
Good answer, but how can I find the equation the altitudes? I know one of them is x=18.. Sorry, I'm useless..
|dw:1334316569993:dw| To find equation of for ex. up right side find the slope: (0-18)/(48-24)=-18/24=-3/4 so equation of line is (y-18) =-3/4(x-24) The perpendicular to this one passing thru the point (0,0): (y-0)=4/3(x-0) Do the same for the rest
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