Question

what is the solution ?

Answer 1

Indeterminate :D

Answer 2

-2.3 -2 x1 = 0
-1 -1.3 x2 0

Answer 3

´-2,3x1-2x2=0
-1x1-1,3x2=0
solve the system

Answer 4

^ i got that What do I do from there.

Answer 5

lol

Answer 6

x2= -2.3/2 * x1
x1= -1.3x2

Answer 7

do I solve for the top in respect to x1 which gives me x2 distribute out x2 from the whole vector?

Answer 8

the solution will be (x1=0,x2=0)

Answer 9

becouse this vectors
-2.3 -2
-1 -1.3
are independent, so no way you can get (0,0) vector from them

Answer 10

in general, the homogeniuos system of equations has a solution diferent from triavial only if it's determinant is equal to 0. In this system it's not the case, so only trivial solution (0,0) exist

Answer 11

I'm trying to diagonalize a 2x2 matrix and I've already determine the eigenvalues using the characteristic equation. Because I can't find the eigenvectors to each corresponding eigenvalue does that mean the 2x2 matrix im trying to diagonalize is cannot be diagonalized?

Answer 12

I am a bit rusty on Algebra, but are the eigenvalues equal, different , eal ?....

Answer 13

yeah they are different.

Answer 14

I am not 100% sure (just don't remember) but just put this eigenvalues on the main diagonal and you have your diagonal matrix

Answer 15

yeah that's D
I'm trying to find P

Answer 16

P?

Answer 17

To show A=PDP^-1
I just need to prove that AP=PD

Answer 18

Eigenvectors of P correspond to eigenvalues of A.

Answer 19

In this problem I was trying to find the eigenvector using matrix A and one of its corresponding eigenvalue

Answer 20

Ima post another questions with what I have done.