Please take a quick look and see if i got the right answer. I just need help on this last question! What is the volume of a triangular prism with a height of 7 inches and a base that is an equilateral triangle with sides of 6 inches?
Im not sure but i got 126in^3
base area = \[\frac{1}{2} \sin 60 \times 6 \times 6\] volume = base area * height i got 15.58 * 7 =109.2 inch....ur wrng :(
Oh well that;s not one of my answer though ;/. The answer are... 147 in3 84sqrt3 in3 126 in3 63sqrt3 in3
well then thers sumthng wrng in the question
ok one sec
The formula for finding the area of a pyramid is V=1/3BH So first we have to do the thing where you find the total for the base but idk how to do it when it says a base that is an equilateral triangle with sides of 6 inches?
After you find the total perimeter of the base then you input the numbers into the formula. I never saw anything about sin beign needed into this problem
haha is it a pyramid or a triangular prism ?
triangle so i made a mistake by saying V=1/3bh instead of V=1/2bh
not quite Area of triangle = 1/2bh Volume = Area of triangle * height of prism
yeah i meant it's a triangular prism
thushananth did it correctly, but just didn't leave it in terms of sqrt3
Oh ok so how do we do that?
its 63sqrt3
oh ok thanks but if it's no trouble can you show me how to work this out?
|dw:1334323177399:dw| if you know trig then sin(60) = h/6 --> h = 6*sqrt3/2 = 3*sqrt3 if you don't know trig then use pythagorean thm h = sqrt(6^2 - 3^2) = sqrt(36-9) = sqrt(27) = 3*sqrt3 Area triangle = 1/2 *6 * 3sqrt3 = 9sqrt3 Volume = 9sqrt3 * 7 = 63sqrt3
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