Question

Create your own third degree polynomial that when divided by x + 2 has a remainder of –4

Answer 1

(-2)^3 + 4(-2)^2 + (-2) -2 = 4
so its
x^3 + 4x^2 + x - 2

Answer 2

i used the Remainder Theorem:
if f(x) is divided by (x + a) then remainder is f(-a)

Answer 3

oh - sorry mape - misread the question - the remainder must be - 4
i'll redo it

Answer 4

we f(-2) to be = -4

(-2)^3 + 4(-2)^2 + (-2) = -8 + 16 -2 = 6
so to get -4 we need to subtract - 10

so the polynomial will be

x^3 + 4(x)^2 + x - 10

Answer 5

ok?

Answer 6

i wonder, can it be any polynomial:

(x+2)(ax^2 + bx + c) - 4

Answer 7

yes it can

Answer 8

yes, using remainder theorem

f(-2) = -4

so if f(x) = (x+2)(ax^2 + bx + c) - 4

for all a,b,c
f(-2) = -4

Answer 9

good thinking

Answer 10

your answer is just as valid