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Mathematics 15 Online
OpenStudy (callisto):

Non-interesting probability problems x 6

OpenStudy (callisto):

That would be easy if you have that sense, but not for me :S

OpenStudy (anonymous):

what sense?

OpenStudy (anonymous):

and so many!!!

OpenStudy (callisto):

For 1and 2, i got the answer. For the rest, still can't work it out

OpenStudy (callisto):

just a few only... there are so many questions that I got wrong

OpenStudy (anonymous):

#3 has grammatical errors.

OpenStudy (callisto):

Which year and the question number?

OpenStudy (callisto):

1991/II/32?

OpenStudy (anonymous):

1992/II/33

OpenStudy (callisto):

^ Explain. Don't just give me the answer. That's not useful

OpenStudy (anonymous):

Told you I am not useful :P

OpenStudy (anonymous):

How many ways we can get a sum 5 in a roll of two dice?

OpenStudy (anonymous):

(1,4),(4,1),(3,2)(2,3)

OpenStudy (anonymous):

Now what about the 10?

OpenStudy (callisto):

(5,5)(6,4)(4,6)

OpenStudy (anonymous):

Yes, so 7/36!

OpenStudy (callisto):

Oh... I see... I know what's wrong with my workings then, thanks

OpenStudy (callisto):

For 1992/II/33, I think the question is correct.

OpenStudy (anonymous):

Yes you are right. My apologies :(

OpenStudy (callisto):

Get back your apologies, I don't need them.

OpenStudy (anonymous):

Why ?

OpenStudy (callisto):

Hmmm...it's strange when people apologise to me...

OpenStudy (anonymous):

Oh I thought you are being rude.

OpenStudy (callisto):

Hmm.. sorry...

OpenStudy (anonymous):

For the apology problem I got 3/10 as answer.

OpenStudy (callisto):

Oh... Yes, I got that too... Sorry that I didn't mentioned

OpenStudy (anonymous):

and for the last problem I am getting 3/5.

OpenStudy (callisto):

Yes, How did you get it?

OpenStudy (anonymous):

For question 1991/II/32, D and E are the same answer... And I can't seem to get any of those either

OpenStudy (anonymous):

For the last problem, you have 2/5*3/4 chances that you'll pick the rotten egg first, and 3/5*2/4 that you'll pick it on second, for a grand total of 12/20 , so 3/5

OpenStudy (callisto):

@m_charron2 1991/II/32 is not a problem now :)

OpenStudy (callisto):

For the last one, I got it now. Thanks :)

OpenStudy (callisto):

What about the first one? 2007/II/33

OpenStudy (anonymous):

Dont' know if there's a quicker when than what I'm about to do, but here we go : You have to pick sums of either 3, 6 or 9. For 3 : (1,2) and (2,1) = 2/(5*4) For 6 : (1,5), (2,4), (4,2) and (5,1) = 4/20 For 9 : 2/20 For a total of 2/5

OpenStudy (callisto):

o.o This is clear enough !!! Thanks :)

OpenStudy (anonymous):

What did you get for 1991/II/32? I got 25/72 (or ((1/6)(5/6)^2)*3) but am not sure

OpenStudy (callisto):

there was a typing mistake there and you're right!

OpenStudy (anonymous):

oh, ok, perfect

OpenStudy (callisto):

So, problems solved. Next one :)

OpenStudy (callisto):

Sorry, just now I discovered a problem. For 2007/II/33, The question stated that the cards are drawn at the same time. I assume that someone pick 2 cards at the same time. Then, the problem comes. Why is (5*4) the base?

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