Non-interesting probability problems x 6
That would be easy if you have that sense, but not for me :S
what sense?
and so many!!!
For 1and 2, i got the answer. For the rest, still can't work it out
just a few only... there are so many questions that I got wrong
#3 has grammatical errors.
Which year and the question number?
1991/II/32?
1992/II/33
^ Explain. Don't just give me the answer. That's not useful
Told you I am not useful :P
How many ways we can get a sum 5 in a roll of two dice?
(1,4),(4,1),(3,2)(2,3)
Now what about the 10?
(5,5)(6,4)(4,6)
Yes, so 7/36!
Oh... I see... I know what's wrong with my workings then, thanks
For 1992/II/33, I think the question is correct.
Yes you are right. My apologies :(
Get back your apologies, I don't need them.
Why ?
Hmmm...it's strange when people apologise to me...
Oh I thought you are being rude.
Hmm.. sorry...
For the apology problem I got 3/10 as answer.
Oh... Yes, I got that too... Sorry that I didn't mentioned
and for the last problem I am getting 3/5.
Yes, How did you get it?
For question 1991/II/32, D and E are the same answer... And I can't seem to get any of those either
For the last problem, you have 2/5*3/4 chances that you'll pick the rotten egg first, and 3/5*2/4 that you'll pick it on second, for a grand total of 12/20 , so 3/5
@m_charron2 1991/II/32 is not a problem now :)
For the last one, I got it now. Thanks :)
What about the first one? 2007/II/33
Dont' know if there's a quicker when than what I'm about to do, but here we go : You have to pick sums of either 3, 6 or 9. For 3 : (1,2) and (2,1) = 2/(5*4) For 6 : (1,5), (2,4), (4,2) and (5,1) = 4/20 For 9 : 2/20 For a total of 2/5
o.o This is clear enough !!! Thanks :)
What did you get for 1991/II/32? I got 25/72 (or ((1/6)(5/6)^2)*3) but am not sure
there was a typing mistake there and you're right!
oh, ok, perfect
So, problems solved. Next one :)
Sorry, just now I discovered a problem. For 2007/II/33, The question stated that the cards are drawn at the same time. I assume that someone pick 2 cards at the same time. Then, the problem comes. Why is (5*4) the base?
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