differentiate sin((1+x2)/(1-x2)), My question is that is a possible substitution possible ???
differentiate means? find derivative?
yes
yes...find d/dx of the function given...
chain and quotient/product
\[\frac{\sin(1+x^2)}{1-x^2}\]? and why do you want to substitute?
i think the sin has the fraction as the argument :)
its chain rule, \[\frac{dy}{dx} = \frac{dy}{du} \frac{du}{dx}\]
\[\sin ((1+x2)\div(1-x2))\]
so let u = (1+x^2)/(1-x^2) so y = sinu now find dy/du and du/dx and multiply to get dy/dx
i know how to diferentiate it using quotient rule etc..but can i substitute any other function in place of x to make it simpler???
@amistre64 - is it possible to substitute any other function in place of x to make it simpler???
we dont tend to substiture for differentiation really, its integration where that comes in handy i mean substituting another function for x.. would it really be worth it? i cant see how it would make it simpler than just quotient ruling it, but if you have a substitution that does please share, i could be wrong
x(x) is already a pretty simple function in its own right
x=trig might produce something different tho ... not sure how simple it would make it tho
suppose in this Q sin(inv)((1-x)/(1+x)) here we sub using cos2x... a similar sub i am asking for...
x = cos2x is not a substitution .... x = cos(2t) might be
ohh
mistype
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