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Evaluate the expression and write the result in the form a + bi.
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\[(4 + 2i)(6 − i)/(2 + i)\]
\[\Large (4+2i)\cdot \frac{6-i}{2+i}=\frac{24-4i+12i-2i^2 }{2+i}\] \[\Large =\frac{24+8i+2 }{2+i}=\frac{26+8i}{2+i}\] \[\Large =\frac{26+8i}{2+i}\cdot \frac{2-i}{2-i}=\frac{52 +16i -26i-8i^2}{2-i^2}=\] \[\Large =\frac{52-10i+8}{2+1}=\frac{ 60-10i}{3}=\] \[ \Large =\frac{60}{3}-\frac{10}{3}i=20-\frac{10}{3}i\]
about rationalizin part im not sure... (Never used it before...) But it seems the only way to get the answer :) ...
auff.... there's a problem.. to the rationalize part you multiply 2 times 2 and you get 4... not 2 , just correct that one.
\[\Large \frac{60 -10i}{5}=...\]
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12-2i
thanks
yw
just used algebra from what i can see right?
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