can x^2+x+2 be factored?
Not with real numbers.
\[{-1 \pm \sqrt{1^2 -(4 \times 1 \times 2)} \over 2} = {-1 \pm \sqrt{-7} \over 2} = {-1\pm \sqrt{7i} \over 2} \]
Nope. To check if a quadratic has real factors or not, check the Discriminant "D" \[D = b^2 - 4ac\] where a,b and ccan be found by comparing your quadratic with the standard form: \[ax^2 + bx +c = 0\] now, if: D=0. --->One real root or factor (that means its a complete square) D>0 --->Two real factors D<0 ---> NO real factors So, what do you think now for the above problem?
I still say it does ;)
It doesn't. Not real factors atleast. :)
how do I solve this problem?
Cross multiply. best way.
so would the answer be x^2 over c+1?
the answer given is 1... i have no clue how
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