Mathematics
7 Online
OpenStudy (anonymous):
if x/2= 3/x+1- 1/2 then x= ?
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OpenStudy (anonymous):
x=-2
x=3
OpenStudy (saifoo.khan):
@MMH123 , do you get how he did it?
OpenStudy (anonymous):
What was your answer?
OpenStudy (anonymous):
no
OpenStudy (saifoo.khan):
\[\frac x2= \frac{3}{x+1}- \frac12\]is it that?
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OpenStudy (anonymous):
yes
OpenStudy (saifoo.khan):
Okay,
let's solve the right side first,
\[\frac x2 = \frac{3 -1(x+1)}{2(x+1)}\]\[\frac x2 = \frac{3 - x - 1}{2x+2}\]
OpenStudy (saifoo.khan):
\[\frac x2 = \frac{2 - x}{2x + 2}\]Cross multiply..
\[x(2x+2) = 2(2-x)\]Can you solve now?
OpenStudy (anonymous):
yeah thanks
OpenStudy (saifoo.khan):
Welcome.
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OpenStudy (asnaseer):
@saifoo.khan you made a slight error up there - the "3 -" should be "6 -"...
OpenStudy (saifoo.khan):
OH! :/
Thanks @asnaseer Bhai.
OpenStudy (asnaseer):
yw
OpenStudy (saifoo.khan):
@MMH123 , there's a mistake..
OpenStudy (anonymous):
what's the mistake?
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OpenStudy (saifoo.khan):
let me do it again..
OpenStudy (saifoo.khan):
Do you mind reposting it?
OpenStudy (saifoo.khan):
nvm.. im solving here.
OpenStudy (saifoo.khan):
\[\frac x2= \frac {3}{x+1}- \frac12\]
Take the LCM 2(x+1)
\[\frac x2 = \frac{3(2) - 1(x+1)}{2(x+1)}\]can u solve from here?
OpenStudy (anonymous):
yeah
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OpenStudy (saifoo.khan):
Cool.
OpenStudy (anonymous):
i cant solve it from there
OpenStudy (saifoo.khan):
\[\frac x2 = \frac{6 - x - 1}{2x+2}\]Now?
OpenStudy (anonymous):
yeah thanks