Simplify (8j3 – 10j2 – 7) – (6j3 – 10j2 – j + 12)

Question

anonymous · Answer

is it 2j3 – j + 5

lgbasallote · Answer

get rid of the grouping symbol by distributing the minus so...

8j^3 - 6j^3 -10j^2 + 10j^2 + j -7 -12 

is that 2j^3 - j + 5? waddyouthink? :D

anonymous · Answer

well thats what I got

hero · Answer

Looks like someone is getting the hang of this. =]

anonymous · Answer

I got 14j^3-20j^2=5 
i use the kfc...

hero · Answer

You used the what?

anonymous · Answer

Keep Flip Change..its easier for me..

hero · Answer

(8j3 – 10j2 – 7) – (6j3 – 10j2 – j + 12) 

8j^3 - 10j^2 - 7 - 6j^3 + 10j^2 + j - 12
8j^3 - 6j^3 - 10j^2 + 10j^2 + j - 7 - 12
2j^3 + j - 19

lgbasallote · Answer

8j^3 - 6j^3 = 2j^3
-10j^2 + 10j^2 = 0
j = j
-7 - 12 = -19

so it should be....im gonna leave that to you

@Winterskull1215 it seems you forgot to distribute the negative sign

anonymous · Answer

darn it..i guess i do suck at math.. :(

hero · Answer

If you put like terms together before adding or subtracting, you'd have much better results.

anonymous · Answer

i guess so.. @Hero

anonymous · Answer

I find out that I forgot a part of the question..