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If the radius of a tumour is increasing at a rate of 0.13cm per month, find the rate of change of the volume. R=0.54cm
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i know that\[V=4/3\pi r^3\]
the rate of change of volume is surface area
V' = 4pi r^2 r'
since the rate of change of the radius with respect to the radius is 1 ... V' = 4pi r^2 ; which is the formula for surface area
ugh, r' is with repect to time tho so lets leave it in
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::: rolls eyes::: :)
ok thank you!
V=4pi (0.54)^2 (0.13)
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