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Mathematics 7 Online
OpenStudy (anonymous):

If the radius of a tumour is increasing at a rate of 0.13cm per month, find the rate of change of the volume. R=0.54cm

OpenStudy (anonymous):

i know that\[V=4/3\pi r^3\]

OpenStudy (amistre64):

the rate of change of volume is surface area

OpenStudy (amistre64):

V' = 4pi r^2 r'

OpenStudy (amistre64):

since the rate of change of the radius with respect to the radius is 1 ... V' = 4pi r^2 ; which is the formula for surface area

OpenStudy (amistre64):

ugh, r' is with repect to time tho so lets leave it in

OpenStudy (amistre64):

::: rolls eyes::: :)

OpenStudy (anonymous):

ok thank you!

OpenStudy (anonymous):

V=4pi (0.54)^2 (0.13)

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