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find the indefinite integral : integral(sin(4x)^3 cos(4x)^4)dx
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Start with u = 4x and du = 4x dx
Now apply the reduction formula.
Did you get it?
wouldn't you want to make the substitution: \[\sin^{3}(4x) = \sin(4x)(1-\cos^{2} (4x))\] \[u = \cos(4x)\] \[du = -4\sin (4x) dx\] \[\rightarrow -\frac{1}{4}\int\limits_{}^{}(1-u^{2})u^{4} du\]
@dumbcow nice one! Its a lot less messier!
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thanks sgamam, can you finish from there
yeah I just finished it thank you both so much for the help!
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