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How do I find the final velocity(after the throw) of the center-of-mass of two skaters?
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m1=82kg, m2 =56kg, velocity of skater 1 and 2 are 4.3m/s. The final velocity is 8m/s for skater 2, and -5.46m/s for skater 1
hello :)
the co-ordinates of the COM is given by r=(m1r1+m2r2....+mnrn)/M so after differentiating the eqn with respect to time, v=m1v1+m2v2+....mnvn)/M this is quite beautiful as we can say the momentum of COM=sum of momentums of the individual p[articles
salini is right. you can differentiate equation i.e. for position of center of mass. or simply you can write it as\[\large V _{cm}=\frac{m _{1}v _{1}+m _{2}v _{2}}{m _{1}+m _{2}}\]but honestly i am little bit confuse by reading your question. well good luck.
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