How do I find the final velocity(after the throw) of the center-of-mass of two skaters?

Question

anonymous · Answer

m1=82kg, m2 =56kg, velocity of skater 1 and 2 are 4.3m/s. The final velocity is 8m/s for skater 2, and -5.46m/s for skater 1

shayaan_mustafa · Answer

hello :)

anonymous · Answer

the co-ordinates of the COM  is given by r=(m1r1+m2r2....+mnrn)/M
so after differentiating the eqn with respect to time,
v=m1v1+m2v2+....mnvn)/M
this is quite beautiful as we can say the momentum of COM=sum of momentums of the individual p[articles

shayaan_mustafa · Answer

salini is right. you can differentiate equation i.e. for position of center of mass. or simply you can write it as$$\large V _{cm}=\frac{m _{1}v _{1}+m _{2}v _{2}}{m _{1}+m _{2}}$$but honestly i am little bit confuse by reading your question. well good luck.