how to determine if points a(-5,-3),b(-1,-1)and c(11,5) are collinear
collinear :three or more points that lie in a straight line
(ab)^2 +bc^2 not equal to ca^2
can you explain?
Get the equation of the line using the first 2 points. Then substitute the last point in this equation to check if it is satisfied. If it is, then it means the 3 points are co-linear.
(graphical method) can be done too, plot the points on a piece of graph paper. You should be able to tell quickly if all the points fall on a straight line. If they don't, they're noncollinear.
how would you get the equasion of the line?
okay an equation to the line is defined by \[y = mx+c\] m = gradient and c = intercept...do u know that?
i know y=mx+b where m is the slope and b is the y intercept
also the slope is 1/2
collinear means that that the slope of two adjacent points will be equal....
so if the slope is the same for the 3 points it is collinear?
yes...
okay so first to get the equation to a line u need to find the "m" which is the slope/gradient so u have two points are a(-5,-3),b(-1,-1) \[m=\frac{{y_{2}-y_{1}}}{x_{2}-x_{1}}\] get the values and substitute to get the M= rather the slope
since slope is same-they all will lie in a same straight line...
but what if the y intcept is different? it isnt collinear then is it?
@Sarkar what is theres another line parellel to that line.?
if*
so???
isnt there a way to determine it accurately?
they are not collinear, assume that theres an equation y=2x+3 and another one y=2x-3 they have differnt y values ( which further proves that the points dont lie on the same line)
Check if slope(ab) = slope(ac).
i don agree
the slopes are equal m=1/2
You're thining a bit wrong thush
i agree @Ishaan94
slope is the gradient right?
rise over run is the slope
Then they are collinear
Yes, slope is gradient.
you are confusing it@thush,you have are considering two lines,why???? the points in Q satisfy only ONE equation not 2..
i thik the equasion is y=-x+2 where the 2 is the y intercept
|dw:1334414331377:dw| what do u say now?
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