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derivative: x^(x+1)^1/2
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\[x ^{\sqrt{x+1}}\]
take log. then differentiate using chain rule and product rule.
ok thanks
\[\sqrt{x+1}/x + lnx/2\sqrt{x+1}\]
is that right?
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http://www.wolframalpha.com/input/?i=Derivative+of+x%5E%28%28x%2B1%29%5E%281%2F2%29%29
derivative: x^(x+1)^1/2 (1/y)dy/dx=(x+1)^1/2 (x)^-1 +lnx/2(x+1)^1/2 dy/dy= y[(x+1)^1/2 (x)^-1 +lnx/2(x+1)^1/2], but y=x^(x+1)^1/2 dy/dx=[x^(x+1)^1/2] [(x+1)^1/2 (x)^-1 +lnx/2(x+1)^1/2] ans..
did you get it azalea?
your answer is correct except you need to multiply them by y=x^(x+1)^1/2
do you want me to show you?
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thank you! can u please show me.
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