The velocity of a 2.4 kg particle changes from 3i-6j to -6i +4j m/s. What is its change in kinetic energy? The velocity of a 2.4 kg particle changes from 3i-6j to -6i +4j m/s. What is its change in kinetic energy? @Mathematics

Question

amistre64 · Answer

what is the formula for kinetic energy?

amistre64 · Answer

1/2 mv is what im thinking but im sure im missing a ^2

anonymous · Answer

Ec = m * 1/2 v^2

apoorvk · Answer

change in kinetic energy  =KE(final) - KE(initial)

Ke = (1/2)mv^2

anonymous · Answer

Sorry, Ke in english LOL

apoorvk · Answer

*KE. lol

amistre64 · Answer

our velocities are just the magnitudes of your vector

anonymous · Answer

oh ok so I can just take the norm of each vector an dthe difference is the answer.

anonymous · Answer

Yes, but I'm curious: could you calculate the difference of the two vectors and use that to calculate the difference in KE?