Question

a colony of bacteria in a culture grows at a rate given by N(t)=2^(t/5), where N is the number of bacteria t minutes from the beginning. The colony is allowed to grow for 60 min, at which time a drug is introduced to kill the bacteria. The number of bacteria killed is given by K(t)=e^(t/3), where K bacteria are killed at t minutes.
a)determine the maximum number of bacteria present and the time at which this occurs

Answer 1

Hello

Answer 2

lol hey, mind answering my question?

Answer 3

Sure. where is it?

Answer 4

the question that i posted?

Answer 5

a colony of bacteria in a culture grows at a rate given by N(t)=2^(t/5), where N is the number of bacteria t minutes from the beginning. The colony is allowed to grow for 60 min, at which time a drug is introduced to kill the bacteria. The number of bacteria killed is given by K(t)=e^(t/3), where K bacteria are killed at t minutes.
a)determine the maximum number of bacteria present and the time at which this occurs

Answer 6

If it continues to grow after the first 60 minutes, the maximum number is something like 478158 bacteria. http://www.wolframalpha.com/input/?i=max+%282%5E%28%28t%2B60%29%2F5%29-e%5E%28t%2F3%29%29

Answer 7

why did u do 2^((t+60)/5)?

Answer 8

because the bacteria have 60 more minutes to grow

Answer 9

They start getting killed 60 minutes after starting to grow

Answer 10

okay, um where did u get 478158 from?

Answer 11

clicked on "approximate form"

Answer 12

can u take me thru the steps to solve for t?

Answer 13

i dont understand the link u sent me