Question

find the area of the region bounded by the line y=x^2 and curve y=1/4 (x-3)^2

Answer 1

First try to find where y=y, you'll get the values where the region ends. Form an integral from where the region starts to where it ends.

Answer 2

y=y --> x^2=1/4*(x-3)^2

Answer 3

Also, make sure what curve lies on top in the region. Now you got an arsenal of hints!

Answer 4

i got up to that part. x=-3 and x=1

Answer 5

\[\int\limits_{-3}^{1} \]

Answer 6

Okay, the integral for the region is going to be of (the upper curve - the lower curve)

Answer 7

the upper curve is x^2 and the lower curve is 1/4(x-3)^2

Answer 8

So take the integral of x^2 - 1/4(x-3)^2

Answer 9

With the bounds you calculated from y=y.

Answer 10

ok. i'll work on it! Thank you!

Answer 11

No problem, good luck! :)

Answer 12

i got -8. is that right?

Answer 13

I'll check!

Answer 14

That would be correct!

Answer 15

thank you :)