Question

Find the equation of the tangent line to y=ln(x-1) at the point (2,0).
-Thanks

Answer 1

y'(x)=1/(x-1)
y'(2) = 1
So line equation is:
y=x-2
If need more explain tell me,:)

Answer 2

Ohh hmm, maybe the answer is wrong. It says y=x+2

Answer 3

do you know why>?

Answer 4

the answer must be wrong ... i guess,

Answer 5

So what is the general method to do this?

Answer 6

I think i am right

Answer 7

Haha thanks but can you explain a little more about how you got this answer?

Answer 8

Like i understand when you get y=1/x-1
But then after, what happens>?

Answer 9

y'(2) gives the slope.
standart equation of line: y-y0=m(x-x0) where (x0,y0) is the point of the line.
rest is easy

Answer 10

Okay, so after you find the derivative, to find the slope at that point,
you sub in x=2?

Answer 11

ya

Answer 12

okay thanks!

Answer 13

you welcome