Question

Abcd is a square with a diagonal of 6 what is the length of a side and area of the square?

Answer 1

S =d^2/2 = 6^2 : 2 = 18
a =b=c=d=\[\sqrt{18}\]

Answer 2

S = d^2 :2
d=6
s= 6^2 : 2 = 18

Answer 3

The side is
\[\sqrt{18}\]

Answer 4

Note the 45-45-90 triangle. That means the ratio of the legs to the hypotenuse (diagonal) is 1:sqrt(2) In this case, the legs will be 3sqrt(2), which means the area is 18.

Answer 5

- so than resulte that (diagonal)^2 = a^2 +b^2 but we know that a=b so than rtesult that
(diagonal)^2 =2a^2 -so than 36=2a^2 - so a^2 = 18 - so a=sqrt18=3sqrt2
than a=b=3sqrt2 from this result that area of square willé be a multiply b what is =a squared so what is 3sqrt2 * 3sqrt2 = 18

Answer 6

ok ?