Question

does anyone know how to do this?
y varies jointly as x and z. write the appropriate joint-variation equation, and find y for the given values of x and z. y= -108, when x= -4, and z= 3, x= 6, and z= -2.

Answer 1

Do you know how to set up the equation?
Joint variation is similar to direct variation, except we have two variables instead of one "\(y=kx\)"

Answer 2

So, the joint variation equation is modelled by \(y = kxz\)
We can find the value of k by substituting the values we know work in the equation (y=-108, x=-4, and z=3) and solving for k.

Then, we just have to insert that k-value and find the new y when x=6 and z=-2

Answer 3

thank youuu!!

Answer 4

You're welcome! :)

Answer 5

Anybody get this answer ?

Answer 6

I'm assuming you need help on this question?

You can find the answer through this process:
\( y = \color{green}kxy \); Plug in: \(y = \neg 108\), \(x = \neg 4\), and \(z = 3\)
\( \neg 108 = \color{green}k( \neg 4)(3) \)
\( \neg 108 = \neg 12 \color{green}k \); Solve for \(\color{green}k\)

Plug the value of \(k\) back into \(y = kxz\) for the more specific equation
To find \(y\) for \(x = 6\) and \(z = \neg 2\), we just plug in this information into our new equation.
\( y = k_{0} (6)(\neg 2) \)

Do you have any specific questions about this problem so that you will understand how to solve them?

Answer 7

I do not mind explaining how to do the problem, but I cannot just give you the answer. :(