Question

How do you find slope intercept form given two points?
Ex: (28,40) and (30,0)

Answer 1

You should find the slope first (y2-y1)/(x2-x1)
x1= 28
x2=30
y1=40
y2=0
Then we will assign that value to be m

now use the equation

(y-y1)= m(x-x1)
sub values into that equation and equate to "y" only
and you should get
y=mx+b

Answer 2

I'm not very... quick with math so I understood the fire sentence. could you make the rest as easy as you can?

Answer 3

first*

Answer 4

Ok so we find the slope first
(y2-y1)/(x2-x1)
i assigned values for x1 x2 y1 and y2
x1= 28
x2=30
y1=40
y2=0
(0-40)/(30-28)
-40/2
We can simplify this fraction by dividing -40 by 2
=-2

-2 will be our slope. the variable used for slope is the letter m
m=-2

Now we will use another equation
y-y1= m(x-x1)
Remember the values that i assigned earlier
y1=40
x1=28
m=-2

I substituted these values into the equation

y-40=-2(x-28)

to simplify this equation, i first distribute (meaning to multiply) -2 to (x-28)
so it becomes -2x+56 (56 becomes positive because negative*negative = positive
our equation so far:

y-40=-2x+28

but we should make it look like the slope intercept form
y=mx+b
but what is b?

we should equate our equation to y only(add 40 to both sides)

y-40+40=-2x+28+40

y=-2x+68

and that's the slope intercept form of the equation :D where the slope is m=-2
and the y-intercept "b" is 68 :D

Answer 5

That's so easy now! Thank you!