A cylindrical vase has a diameter of 6 inches. At the bottom of the vase, there are 6 marbles, each of diameter 2 inches. The vase is filled with water up to a height of 10 inches.

What is the volume of water in the vase?
Answer
36π in3
54π in3
66π in3
82π in3

Question

A cylindrical vase has a diameter of 6 inches.  At the bottom of the vase, there are 6 marbles, each of diameter 2 inches. The vase is filled with water up to a height of 10 inches.
 
What is the volume of water in the vase?
Answer
		36π in3
		54π in3
		66π in3
		82π in3

alexwee123 · Answer

agh its easier to explain if i could draw but i suck at drawing on the comp -_-

anonymous · Answer

will you explain how to get the answer please

anonymous · Answer

im having alot of trouble

amistre64 · Answer

$$V_c-6V_s$$

anonymous · Answer

so the answer is?

anonymous · Answer

cause i honestly have no idea

amistre64 · Answer

then the answer isnt going to help out to much

jlastino · Answer

|dw:1334452138947:dw| 
So compute the  volume of vase (which is cylindrical)
Volume of cylinder =pi*r^2*h
The diameter is 6 inches divide this by 2 to get the tadius
r=3
Since the problem says "The vase is filled with water up to a height of 10 inches."
we assume that the height of the vase is 10
h=10
use that in the equation

pi*3^2*10
this will give
90pi (but this isn't the amount of water yet)

Calculate the volume of one marble (which are spherical in shape)

Volume of sphere (4/3)*pi*r^3
r=1
(4/3)*pi*1^3
(4/3)pi
then multiply it by 6 (there are 6 marbles

6(4/3)*pi
24/3pi
8pi

Then subtract this from the volume of the vase
90pi-8pi

=82pi