Question

@callisto, help here please

Answer 1

@callisto

Answer 2

for a, it is a cosine function
its magnitude is magnified by 4 => a=4
look at the period,
it has a period of 1440, which is 4 times the original one => b= 1/4

Answer 3

so for a, the first graph is y = 4cos(1/4 x)?

Answer 4

I hope so :)

Answer 5

hey ...

Answer 6

Cool~ @mathg8 is going to correct my mistakes :)

Answer 7

looks good

Answer 8

hey @mathg8, for graph 1 of problem a, is y = 4cos(1/4 x) correct?

Answer 9

yes ... you can always graph and check your solutions

Answer 10

https://www.desmos.com/calculator

Answer 11

@mathg8 are you going to teach us how to use GeoGebra?

Answer 12

Oh yeah! it is correct:)

Answer 13

it's pretty easy ...you just have to play

Answer 14

Good website :)
I've tried, but I'm a tech-idiot :(

Answer 15

@mathg8, that site is amazing!

Answer 16

you have to know geometry pretty well to be able to use most of the features

Answer 17

For the second graph, how can i Determine the equation of each graph in the form y = acos(bx)?

Answer 18

glad you like it ...

Answer 19

hold on ...digging for something for you

Answer 20

For the first one, how did you determine the a and b values?

Answer 21

site crashed ?

Answer 22

i think so. I just logged on

Answer 23

me too

Answer 24

the bottom of the page tells all ....

Answer 25

so does that mean the equation is y = 3cos(3 x)?

Answer 26

for the second graph?

Answer 27

there is a phase shift for the second one , can you find it ?

Answer 28

before that what is the period ?

Answer 29

Can I determine the period if there are not enough cycles in the graph

Answer 30

yes

Answer 31

I thought to determine the period, we calculate the The horizontal distance between cycles

Answer 32

Ies the period then 90degrees?

Answer 33

basically , three parts of the graph are given

Answer 34

One second

Answer 35

Im not sure how to find the period without more cycles