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Mathematics 11 Online
OpenStudy (anonymous):

@callisto

OpenStudy (anonymous):

The other place is too messy

OpenStudy (callisto):

Part b?!

OpenStudy (anonymous):

Yeah of the question. We solved only part a. He had to leave

OpenStudy (anonymous):

For graph 1 of part b, No matter what I put for the value of b, why does it always cross at 0 in the y axis?

OpenStudy (callisto):

I think it would be easier to start with the second graph. it looks like a sine function.

OpenStudy (anonymous):

Does this kind of make sense? y = 4sin(x+360)

OpenStudy (callisto):

you mean for the first graph?

OpenStudy (anonymous):

Yes

OpenStudy (callisto):

sin(x+360) = sinx ....

OpenStudy (anonymous):

Because when I graph that, It is very identical

OpenStudy (anonymous):

OK, If its not, Lets do graph 2 first:)

OpenStudy (callisto):

Please give me few minutes or so. Let me graph it first :)

OpenStudy (anonymous):

wow. y = 4sin(x+ pi/2) gives me the exact same graph

OpenStudy (callisto):

Actually... if you just take a look of the shape... That wouldn't help much..

OpenStudy (anonymous):

Oh.

OpenStudy (callisto):

Some problems with that graph , sorry

OpenStudy (anonymous):

Oh ok:)

OpenStudy (callisto):

That is it! \[y=4\sin \left(\frac{\pi }{2}-\frac{1}{4}x\right)\]

OpenStudy (anonymous):

It is?

OpenStudy (anonymous):

This is for graph 1 right?

OpenStudy (callisto):

the first graph...

OpenStudy (anonymous):

How did you determine the values of a and b?

OpenStudy (callisto):

Suddenly, I remember that cos(x) = sin(90- x).. As you've got the result from (a), amplitude would be unchanged So, the change cos to sin -> y= 4 (90 - (1/4 x ) ) => y=4(90 - 1/4 x ) the pi/2 is 90 degree in radian

OpenStudy (anonymous):

Does this answer also work? y=−4sin1/4(x−360)

OpenStudy (callisto):

That is the same, just multiply the numbers and take out -1 as a factor, giving you the same solution

OpenStudy (anonymous):

Mertsj, told me that we shouldnt use pi because the graph is in degrees

OpenStudy (anonymous):

If that is true, I have to change all my answer:(

OpenStudy (callisto):

Hmm... I told you in the last solution... y=4(90 - 1/4 x )... Sorry.. I'm not good at all

OpenStudy (anonymous):

Ok, so for part a, how would I change this? -3cos(2 x – pi/2).

OpenStudy (anonymous):

same thing?

OpenStudy (anonymous):

-3cos(2 x – 90).

OpenStudy (callisto):

If '-3cos(2 x – pi/2)' is correct, then it is correct

OpenStudy (anonymous):

Ok:). so for problem a the answer is y=4(90 - 1/4 x )

OpenStudy (callisto):

I think so, I'm not sure

OpenStudy (anonymous):

this is so strange, Icannot graph the equations

OpenStudy (anonymous):

Ok, how do we solve the last question!

OpenStudy (callisto):

OpenStudy (anonymous):

not !, but? sorry, lol

OpenStudy (anonymous):

Little typo sounds so different. hahah

OpenStudy (callisto):

lol you can see I'm opening so many things at the same time.. I should hide it next time hehe~

OpenStudy (anonymous):

lol.

OpenStudy (anonymous):

Should I just use pi in my equations?

OpenStudy (callisto):

nope... pi =180 degrees... you need to change it

OpenStudy (anonymous):

How do we solve the second one?

OpenStudy (callisto):

Time to graph again~ Please wait again :(

OpenStudy (anonymous):

Ok, Il try it as well. Btw, thank you for your help:)

OpenStudy (callisto):

This one is easier :)

OpenStudy (anonymous):

so for the first one, a = 4 and b = pi/2 - 1/4 and for the second on, a = -3, b = 2 Is this correct?

OpenStudy (anonymous):

@callisto, is that correct?

OpenStudy (callisto):

Not really..

OpenStudy (anonymous):

but those are the values for the equations

OpenStudy (callisto):

bx.....

OpenStudy (callisto):

pi/2,in which you should write 90, is a constant in the cosine function

OpenStudy (anonymous):

But if replace pi/2 with 90, my graph changes

OpenStudy (callisto):

because .... the axis is different.....

OpenStudy (anonymous):

OpenStudy (anonymous):

I will get this instead

OpenStudy (callisto):

I know....but you need the answer in degrees, right?

OpenStudy (anonymous):

Yes, so how can I have my answer in degree,while not ruining the graph?

OpenStudy (callisto):

You need to hand in the graph as well?

OpenStudy (anonymous):

I think so

OpenStudy (callisto):

Hmm..hand in through computer?

OpenStudy (anonymous):

what are the values of a and b in the first graph?

OpenStudy (anonymous):

If my values are wrong, I need to know what the values are

OpenStudy (callisto):

I think you need to have a constant term... Can you?

OpenStudy (anonymous):

What do you mean?

OpenStudy (callisto):

Let say, for first graph - question b y=4(90 - 1/4 x ) y = a(c - bx) a = 4, b=-1/4 and you 'll need a c

OpenStudy (anonymous):

isnt c in this case 90 then>?

OpenStudy (callisto):

yes

OpenStudy (anonymous):

Yes but the graph comes out like this http://assets.openstudy.com/updates/attachments/4f8a3e36e4b09e61bffbf6a1-open2study-1334463738275-capture.png

OpenStudy (anonymous):

It doesnt cross in 4 at the y-axis

OpenStudy (callisto):

x is not the angle... I'm confused:S!!!!

OpenStudy (callisto):

For the 1st graph, a = 4 and and b - ¼. A constant should be add in the functin, so it becomes y=asin(bx+c), where c = 90degrees(also equal to pi/2)Therefore, the equation is y = 4sin(90degrees – ¼ x)

OpenStudy (anonymous):

Oh. ok, I see where I got it wrong. How about the 2nd graph?

OpenStudy (anonymous):

@callisto?

OpenStudy (callisto):

It should be correct. Sorry :(

OpenStudy (anonymous):

Ok. Thank you:) 1 more question for this assignment.

OpenStudy (callisto):

Okay!~ I have to be concentrated this time!!

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