@callisto
The other place is too messy
Part b?!
Yeah of the question. We solved only part a. He had to leave
For graph 1 of part b, No matter what I put for the value of b, why does it always cross at 0 in the y axis?
I think it would be easier to start with the second graph. it looks like a sine function.
Does this kind of make sense? y = 4sin(x+360)
you mean for the first graph?
Yes
sin(x+360) = sinx ....
Because when I graph that, It is very identical
OK, If its not, Lets do graph 2 first:)
Please give me few minutes or so. Let me graph it first :)
wow. y = 4sin(x+ pi/2) gives me the exact same graph
Actually... if you just take a look of the shape... That wouldn't help much..
Oh.
Some problems with that graph , sorry
Oh ok:)
That is it! \[y=4\sin \left(\frac{\pi }{2}-\frac{1}{4}x\right)\]
It is?
This is for graph 1 right?
the first graph...
How did you determine the values of a and b?
Suddenly, I remember that cos(x) = sin(90- x).. As you've got the result from (a), amplitude would be unchanged So, the change cos to sin -> y= 4 (90 - (1/4 x ) ) => y=4(90 - 1/4 x ) the pi/2 is 90 degree in radian
Does this answer also work? y=−4sin1/4(x−360)
That is the same, just multiply the numbers and take out -1 as a factor, giving you the same solution
Mertsj, told me that we shouldnt use pi because the graph is in degrees
If that is true, I have to change all my answer:(
Hmm... I told you in the last solution... y=4(90 - 1/4 x )... Sorry.. I'm not good at all
Ok, so for part a, how would I change this? -3cos(2 x – pi/2).
same thing?
-3cos(2 x – 90).
If '-3cos(2 x – pi/2)' is correct, then it is correct
Ok:). so for problem a the answer is y=4(90 - 1/4 x )
I think so, I'm not sure
this is so strange, Icannot graph the equations
Ok, how do we solve the last question!
not !, but? sorry, lol
Little typo sounds so different. hahah
lol you can see I'm opening so many things at the same time.. I should hide it next time hehe~
lol.
Should I just use pi in my equations?
nope... pi =180 degrees... you need to change it
How do we solve the second one?
Time to graph again~ Please wait again :(
Ok, Il try it as well. Btw, thank you for your help:)
This one is easier :)
so for the first one, a = 4 and b = pi/2 - 1/4 and for the second on, a = -3, b = 2 Is this correct?
@callisto, is that correct?
Not really..
but those are the values for the equations
bx.....
pi/2,in which you should write 90, is a constant in the cosine function
But if replace pi/2 with 90, my graph changes
because .... the axis is different.....
I will get this instead
I know....but you need the answer in degrees, right?
Yes, so how can I have my answer in degree,while not ruining the graph?
You need to hand in the graph as well?
I think so
Hmm..hand in through computer?
what are the values of a and b in the first graph?
If my values are wrong, I need to know what the values are
I think you need to have a constant term... Can you?
What do you mean?
Let say, for first graph - question b y=4(90 - 1/4 x ) y = a(c - bx) a = 4, b=-1/4 and you 'll need a c
isnt c in this case 90 then>?
yes
Yes but the graph comes out like this http://assets.openstudy.com/updates/attachments/4f8a3e36e4b09e61bffbf6a1-open2study-1334463738275-capture.png
It doesnt cross in 4 at the y-axis
x is not the angle... I'm confused:S!!!!
For the 1st graph, a = 4 and and b - ¼. A constant should be add in the functin, so it becomes y=asin(bx+c), where c = 90degrees(also equal to pi/2)Therefore, the equation is y = 4sin(90degrees – ¼ x)
Oh. ok, I see where I got it wrong. How about the 2nd graph?
@callisto?
It should be correct. Sorry :(
Ok. Thank you:) 1 more question for this assignment.
Okay!~ I have to be concentrated this time!!
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