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Mathematics 16 Online
OpenStudy (anonymous):

8. How does the graph of y = -3cos(2θ + 45°) + 3 differ from the graph of y = cos(θ)?

OpenStudy (anonymous):

one sec, Il brb

OpenStudy (anonymous):

i'm here to to the answer ... jst :)

OpenStudy (anonymous):

How did you do on those homework problems? How far off was I?

OpenStudy (accessdenied):

its a lot of shifts, reflecting, and compressing of the graph of cos theta. ;[

OpenStudy (anonymous):

OK, Im back:)

OpenStudy (anonymous):

open study follow me i can help u i think so .....

OpenStudy (anonymous):

Follow you where?

OpenStudy (anonymous):

open2study first sketch the basic graph for cos \[\Theta\]

OpenStudy (anonymous):

hahaahahahaha .. here ... :D

OpenStudy (anonymous):

I got ya! Let me work it out!:D

OpenStudy (anonymous):

now sketch the graph for \[2\Theta\]

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

u will find that the original graph is stretched now by 2

OpenStudy (anonymous):

the original graph will stretched now by 2 vertically

OpenStudy (anonymous):

It has a period of pie, Its amplitude is -3, its vertical shift is 3, its phase shift is 45/2 to the right. I think? :D

OpenStudy (anonymous):

Not sure if right ^ Havent done in a while.

OpenStudy (anonymous):

did u get me till now? i will bring u to where u need to reach :)

OpenStudy (anonymous):

yup:), I understand

OpenStudy (anonymous):

^ all those answers are incorrect btw.

OpenStudy (anonymous):

really?

OpenStudy (anonymous):

now u got second graph that is cos ( \[2\Theta\] ) and add 45 to cos (\[2\Theta\] ) and sketch this new graph .. u will find that graph is shifted toward neg x axis by 45 deg

OpenStudy (anonymous):

@petewe, what is the correct answer?

OpenStudy (anonymous):

45 deg = pi / 4

OpenStudy (anonymous):

-3cos(2θ + 45°) + 3 -vertical stretch by factor of 3 -reflection on x axis -horizontal compression by factor of 1/2 -horizontal translation of 22.5 left -vertical translation 3 up.

OpenStudy (anonymous):

don't know why the last guy is converting degrees to radians when the original function is clearly in degrees.

OpenStudy (anonymous):

@pet bcoz i jst wanted to make the asked understand that is why

OpenStudy (anonymous):

the asker*

OpenStudy (anonymous):

Thank you @petewe, Thank @Jatinbansalhot, the both of you helped so much:)

OpenStudy (anonymous):

open2study.... you are welcome.... i am new i jst tried my best...

OpenStudy (anonymous):

@jatinbansalhot, its good that you are trying hard. Peole in OS need users like you who try their very besst. dont change that:)

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