8. How does the graph of y = -3cos(2θ + 45°) + 3 differ from the graph of y = cos(θ)?
one sec, Il brb
i'm here to to the answer ... jst :)
How did you do on those homework problems? How far off was I?
its a lot of shifts, reflecting, and compressing of the graph of cos theta. ;[
OK, Im back:)
open study follow me i can help u i think so .....
Follow you where?
open2study first sketch the basic graph for cos \[\Theta\]
hahaahahahaha .. here ... :D
I got ya! Let me work it out!:D
now sketch the graph for \[2\Theta\]
ok
u will find that the original graph is stretched now by 2
the original graph will stretched now by 2 vertically
It has a period of pie, Its amplitude is -3, its vertical shift is 3, its phase shift is 45/2 to the right. I think? :D
Not sure if right ^ Havent done in a while.
did u get me till now? i will bring u to where u need to reach :)
yup:), I understand
^ all those answers are incorrect btw.
really?
now u got second graph that is cos ( \[2\Theta\] ) and add 45 to cos (\[2\Theta\] ) and sketch this new graph .. u will find that graph is shifted toward neg x axis by 45 deg
@petewe, what is the correct answer?
45 deg = pi / 4
-3cos(2θ + 45°) + 3 -vertical stretch by factor of 3 -reflection on x axis -horizontal compression by factor of 1/2 -horizontal translation of 22.5 left -vertical translation 3 up.
don't know why the last guy is converting degrees to radians when the original function is clearly in degrees.
@pet bcoz i jst wanted to make the asked understand that is why
the asker*
Thank you @petewe, Thank @Jatinbansalhot, the both of you helped so much:)
open2study.... you are welcome.... i am new i jst tried my best...
@jatinbansalhot, its good that you are trying hard. Peole in OS need users like you who try their very besst. dont change that:)
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