If Logx (1 / 8) = - 3 / 2, then x is equal to
Log_x(1/2) = -3/2 is the same as x^(-3/2) = 1/2
x^(-3/2 = 1/2 .. i think you can try these
Logrithmic rules 1) log_b(mn) = log_b(m) + logb(n) 2) log_b(m/n) = log_b(m) – logb(n) 3) log_b(m^(n)) = n · log_b(m) 4) log_3(3) = 1 5) log_e(x) = ln(x) 6) log(x) = y is the same as x =10^(y) 7) log_10(x) = log(x)
1 / x^3/2 = 1/2 right?
yes
x^(-3/2) = 1/2 Raise both sides of the euqation by the power of 2 x^(-6/2) = (1/2)^(2) x^(-3) = (1/2)^(2) Now take the negative cube root of both sides x = (1/2)^(-2/3)
its not 1/2 its 1/8 .. waa my mistake
8 = x^3/2 8 = sqrt x^3 64 = x^3 then x=4?
2^(2/3) is the answer if it was 1/8 8^(-1)^(-2/3) = 8^(2/3)
yes you are right
simple algebra
@ampohmeow i think it is
thanks a lot .. even its simple .. im here to learn
way to go ampohmeow .. you can post questions here if you like ..
Yeah we all have to start somewhere I was having a hard time with this math just 8 months ago now I'm getting 90s on calc I midterms
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