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Question

anonymous · Answer

A person standing near the edge of the top of a building thrown 2 balls A and B. The ball A is thrown vertically upward and B is thrown vertically downward with the same speed. The ball A hits the ground with a speed v(a) and the ball B hits the ground with a speed v(b). We have:
a/ v(a)>v(b)
b/ vice versa
c/ v(a)=v(b)
d/ the relation between the velocities depends on height of the building above the ground

anonymous · Answer

V(b) will be greater then v(a) because the force at which ball B is thrown is in the direction of gavitation  so there is gravitational pull in cause of A in the direction of force at which ball is thrown is opposite to the the gravitation.

anonymous · Answer

The ans is c 
they are equal i just need an exp

mani_jha · Answer

Let the height be h.
Think  of conservation of mechanical energy.

anonymous · Answer

Answer is Option (c).

anonymous · Answer

?

anonymous · Answer

dont they fall different heights?

mani_jha · Answer

yes. What is the total energy of the bodies in the initial state when they are both thrown?
Hint: Kinetic energy+Potential energy
Then what is the total energy when the body thrown down touches the ground? Use energy conservation to find this body's velocity.
Finally, what is the total energy when the body thrown up touches the ground? Use  energy conservation to find this body's velocity.