Sorry for asking so many questions but I'm completely lost so here's another one. How would I simplify this problem and rewrite it in an equivalent form with positive exponents (-x^-3)^-5

Question

anonymous · Answer

$$a^{-2}=1/a^2$$

jlastino · Answer

Just make it 1/(given equation)      (because it is raised to a negative exponent)

anonymous · Answer

So I would make it a division problem insted of a multiplication?

jlastino · Answer

I think so but what you are doing is just expressing it more clearly (simplifying)

anonymous · Answer

Would I add the two exponents together or just leave it the same? 1/(-x^-3)^-5, like that

jlastino · Answer

You make the exponent positive

jlastino · Answer

then multiply since (x^a)^b = (x^ab)

anonymous · Answer

Ok, I think I understand now. Thanks for the help :)

jlastino · Answer

Could you show me the answer? :D

anonymous · Answer

(-x^-3)^-5=
(-x^8), is that corret?

jlastino · Answer

No....keep in mind when you raise an exponent by an exponent you multiply them

anonymous · Answer

Oh so I would multiply -3 by -5

anonymous · Answer

Is the correct answer 1/(-x^15)

jlastino · Answer

i think so, yeah

jlastino · Answer

oh wait...it should be -x^15

anonymous · Answer

Ok, thanks