Question

Please help me!

Answer 1

\[5x^{3}y + xy ^{4}+2xy \div xy\]

Answer 2

except its suppose to be in fraction form...

Answer 3

is 5x^3y + xy^4 + 2xy in the numerator?

Answer 4

its the top and the xy is on the bottom

Answer 5

Oh just reduce every exponent of x and y in the numerator by 1 then the denominator would be gone

Answer 6

huh?

Answer 7

so 5x^2+y^3+2?

Answer 8

yup

Answer 9

oh lol okay thank you

Answer 10

^ that's actually incorrect, close though.

Answer 11

you did it right, Riya.... good job

Answer 12

-.-

Answer 13

RiyaMoon: what you have is totally correct.
\[5x^3y+xy^4+2xy=xy(5x^2+y^3+2)\]therefore:\[\frac{5x^3y+xy^4+2xy}{xy}=\frac{\cancel{xy}(5x^2+y^3+2)}{\cancel{xy}}=5x^2+y^3+2\]

Answer 14

I have no idea why you're multiplying the right side by xy(5x^2 + y^2 + 2), that's completely incorrect.

Answer 15

@petewe 5x^3 is different from (5x)^3

Answer 16

woops, read the equation wrong