Question

HELP!(:
Describe the vertical asymptote(s) and hole(s) for the graph of
y=(x-5)(x-2)/(x-2)(x+4)

Answer 1

Look at your numerator and denominator.
If there are any of the same term in both, you can cancel them out right? This tells you there's a hole at x = whatever.
You can find the vertical asymptote like how we discussed earlier.

Answer 2

\[\frac{ab}{bd}\]
VA = d, hole = b

Answer 3

well, when those zero ouot that is :)

Answer 4

The horizontal asymptote would be dividing the lead term of num and dem, for future reference.

Answer 5

forbidden knowledge ...

Answer 6

@petewe i see

Answer 7

would the asymptote be -4?

Answer 8

yea

Answer 9

thats your vertical asymptote, your horizontal would be x=1.

Answer 10

@ash2326 do u agree also that the asymptote would be -4?

Answer 11

and would the hole be x=2?

Answer 12

yep

Answer 13

thanks