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Mathematics 16 Online
OpenStudy (anonymous):

HELP!!(: Simplify the rational expression. State any restrictions on the variable. p^2 - 4p - 32 / p + 4

OpenStudy (anonymous):

@petewe @jlastino @ash2326 can you guys help me solve and understand this?

OpenStudy (anonymous):

I suppose you would just factor the numerator and state your asymptotes.

OpenStudy (jlastino):

one restriction is the denominator can't be 0 cause that will make the function undefined so you equate the denominator to 0

OpenStudy (apoorvk):

factorise the numerator, and then cancel out like terms. how ever do not froget to post the constraint that p UNEQUAL to -4. since at p=-4 the function is not defined.

OpenStudy (anonymous):

but in this case p = -4 is a hole, so there is no asymptote.

OpenStudy (anonymous):

it's a linear with a hole at -4

OpenStudy (anonymous):

@apoorvk @petewe @jlastino so its either \[-p-8; p \neq -4\] or \[p-8; p \neq -4\]

OpenStudy (anonymous):

Not quite, there would be no restrictions because there is no asymptote.

OpenStudy (anonymous):

@petewe then what would it be and why?

OpenStudy (anonymous):

It would simply be a linear equation: (p-8) with a hole.

OpenStudy (anonymous):

well thats not in any of the answers i can choose for my extra credit

OpenStudy (anonymous):

@petewe well thats not in any of the answers i can choose for my extra credit

OpenStudy (anonymous):

@petewe so that cant be it

OpenStudy (anonymous):

@apoorvk what do you think?

OpenStudy (apoorvk):

What are your options?

OpenStudy (anonymous):

@apoorvk the two equations i had earlier as you can see above and \[-p-8; p \neq 4\] or \[p+8; p \neq 4\]

OpenStudy (anonymous):

@apoorvk and @petewe look above

OpenStudy (apoorvk):

I think there's some error in the option, should be "p-8". Is a printing or a typing error a possibility?

OpenStudy (anonymous):

@apoorvk but i'll choose the only one that has p-8

OpenStudy (anonymous):

@apoorvk thanks for your help!

OpenStudy (apoorvk):

no worries! :)

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