looking for the discriminant (b^ - 4ac), if the formula is 4x^ + 4x + 1 = 0 am I right in thinking this will become, 4x^ - 4 x 16 x 1 which equals -48 and therefore there are no solutions?

Question

turingtest · Answer

not quite...
what is b ?
what is a ?
what is c ?

anonymous · Answer

a = 4x squared
b = 4x
c= 1

turingtest · Answer

no, a, b, and c are just the coefficients (the numbers)
do not include the x part

anonymous · Answer

a = 4
b = 4
c = 1

turingtest · Answer

so now what do you get for the discriminant?

anonymous · Answer

- 48?

turingtest · Answer

4^2-4(4)(1)=-48 ?
I don't think so, recheck your arithmetic

anonymous · Answer

I'm happy with the first part, 4^2 = 16
I think B is confusing me is it -4x4 which is -16 + 1(c) so total answer = 1?

turingtest · Answer

4^2=16
4(4)(1)=16
so
4^2-4(4)(1)=16-16

anonymous · Answer

of course because your multiplying AxBxC 
so 16- 16x1 = 0
so back to the original question now you've helped me with this as the discriminant is now 0 that means there can only be one solution? correct?

turingtest · Answer

yes, a "double root" of one real number

anonymous · Answer

thank you for your assistance Master Maths Jedi! :)

turingtest · Answer

ah, very welcome you are
force be with you ;)