Question

pls help

Answer 1

a)express AB, AM, OM in terms of a and b
b) given that G lies on OM such that OG:GM=2:1, express OG in terms of a and b
c) Express AG in terms of a and b
d) Express AN in terms of a and b
e) show that AG=mAN and find the value of m?

Answer 2

Is AM=MB?

Answer 3

ye s it and BN=ON too sorry fr nt saying

Answer 4

AB= OB-OA
=b-a

AM= (b-a)/2

OM=AM-AO
= (b-a)/2+a
=(a-b)/2

Answer 5

OM=OA+AM
a-1/2a+1/2b
=(a+b)/2 this is crct

Answer 6

Yes. You can either do Vector Addition or Vector Subtraction. Both ways are correct.

Answer 7

nope bt ths not the answer

Answer 8

Oh sorry. I put subtraction sign instead of addition.
The answer does come (a+b)/2

Answer 9

u dint add yeah ok..do the next ones

Answer 10

OG:GM
2:1
Thus 2/3 x (a+b)/2
OG= (a+b)/3

Answer 11

ok

Answer 12

u there?

Answer 13

AG= (b-2a)/ 3

AN= (b-2a)/2

AG=mAN
(b-2a)/3 x 2/(b-2a)= m
m=2/3

Answer 14

cn u explain AG part?

Answer 15

AG= AO+OG
=-a+ (a+b)/3
= (b-2a)/3

Answer 16

i mean the last part? AG=mAN

Answer 17

Oh. Sorry.
You see the question says AG= mAN
So you put the values of AG and AN we found earlier.
\[(b-2a) \div3= m \left[ (b-2a)\div2 \right] \]
Now moving the values so that m is left alone, you get the answer m= 2/3

Answer 18

okay thanks alot...:D i owe u alot...sis...if u need any doubt regrding physics im there to help...

Answer 19

YW. I'll post a question in a sec. :D

Answer 20

sure