Question

I need help with limits

Answer 1

\[\lim_{x \rightarrow 0} (1-\cos^2x)/(3sinx)\]

Answer 2

use the identity\[\sin^2x+\cos^2x=1\]to simplify the expression

Answer 3

trig really throws me off my game

Answer 4

so the entire numerator is = sin^2x

Answer 5

yup

Answer 6

ok so then does my sinx on top and sinx on bottom cancel out?

Answer 7

one of 'em does
it's sin^2 on top....

Answer 8

ok i see so then its sinx over 3 ok

Answer 9

but even then when i plug zero into sin(0) then that leaves me with 0/3

Answer 10

great, so what's wrong with that?

Answer 11

haha zero didnt sound like the right answer but it was thanks alot

Answer 12

welcome :)