Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (shayaan_mustafa):
sure friend.
OpenStudy (anonymous):
Btw, its only question1 not all of them:)
OpenStudy (shayaan_mustafa):
let us solve Q#1
OpenStudy (anonymous):
Yes:)
OpenStudy (shayaan_mustafa):
Write the given question in the general form as.\[\large y=Atan[B(x-(\frac{C}{B}))]+C\]\[\large y=-2\tan[3(x-(-\frac{\pi}{3}))]+3\]
Now compare results
amplitude=|A|=-2
Period=2*pi/B 2*pi/3
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (shayaan_mustafa):
Thnx for testimonial friend. :)
OpenStudy (anonymous):
Wait, but how come there is a pi/3 in the equation?
OpenStudy (shayaan_mustafa):
it don't have vertical asymptote but two horizontal asymptote.
OpenStudy (shayaan_mustafa):
180degree = pi radians.
OpenStudy (anonymous):
Oh thats right:)
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
so the period is 2*pi/3
OpenStudy (shayaan_mustafa):
yes.
OpenStudy (anonymous):
Ok. Is this range correct?
{y | y is an element or R}
OpenStudy (shayaan_mustafa):
yes. range will be all real numbers.
OpenStudy (anonymous):
What would my domain be? This one in particular I am having the most trouble with
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (campbell_st):
one simple problem is that tan has a period of pi... and not 2pi... so the period is pi/3
for the tan graph... the -2 means there curve is reversed|dw:1334526511685:dw|
+3 means the centre of the curve is moved up to the line y = 3